3.1398 \(\int \frac{(5-x) (3+2 x)^3}{\sqrt{2+3 x^2}} \, dx\)

Optimal. Leaf size=84 \[ -\frac{1}{12} \sqrt{3 x^2+2} (2 x+3)^3+\frac{31}{36} \sqrt{3 x^2+2} (2 x+3)^2+\frac{5}{54} (171 x+809) \sqrt{3 x^2+2}+\frac{275 \sinh ^{-1}\left (\sqrt{\frac{3}{2}} x\right )}{3 \sqrt{3}} \]

[Out]

(31*(3 + 2*x)^2*Sqrt[2 + 3*x^2])/36 - ((3 + 2*x)^3*Sqrt[2 + 3*x^2])/12 + (5*(809 + 171*x)*Sqrt[2 + 3*x^2])/54
+ (275*ArcSinh[Sqrt[3/2]*x])/(3*Sqrt[3])

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Rubi [A]  time = 0.0428908, antiderivative size = 84, normalized size of antiderivative = 1., number of steps used = 4, number of rules used = 3, integrand size = 24, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.125, Rules used = {833, 780, 215} \[ -\frac{1}{12} \sqrt{3 x^2+2} (2 x+3)^3+\frac{31}{36} \sqrt{3 x^2+2} (2 x+3)^2+\frac{5}{54} (171 x+809) \sqrt{3 x^2+2}+\frac{275 \sinh ^{-1}\left (\sqrt{\frac{3}{2}} x\right )}{3 \sqrt{3}} \]

Antiderivative was successfully verified.

[In]

Int[((5 - x)*(3 + 2*x)^3)/Sqrt[2 + 3*x^2],x]

[Out]

(31*(3 + 2*x)^2*Sqrt[2 + 3*x^2])/36 - ((3 + 2*x)^3*Sqrt[2 + 3*x^2])/12 + (5*(809 + 171*x)*Sqrt[2 + 3*x^2])/54
+ (275*ArcSinh[Sqrt[3/2]*x])/(3*Sqrt[3])

Rule 833

Int[((d_.) + (e_.)*(x_))^(m_)*((f_.) + (g_.)*(x_))*((a_) + (c_.)*(x_)^2)^(p_.), x_Symbol] :> Simp[(g*(d + e*x)
^m*(a + c*x^2)^(p + 1))/(c*(m + 2*p + 2)), x] + Dist[1/(c*(m + 2*p + 2)), Int[(d + e*x)^(m - 1)*(a + c*x^2)^p*
Simp[c*d*f*(m + 2*p + 2) - a*e*g*m + c*(e*f*(m + 2*p + 2) + d*g*m)*x, x], x], x] /; FreeQ[{a, c, d, e, f, g, p
}, x] && NeQ[c*d^2 + a*e^2, 0] && GtQ[m, 0] && NeQ[m + 2*p + 2, 0] && (IntegerQ[m] || IntegerQ[p] || IntegersQ
[2*m, 2*p]) &&  !(IGtQ[m, 0] && EqQ[f, 0])

Rule 780

Int[((d_.) + (e_.)*(x_))*((f_.) + (g_.)*(x_))*((a_) + (c_.)*(x_)^2)^(p_), x_Symbol] :> Simp[(((e*f + d*g)*(2*p
 + 3) + 2*e*g*(p + 1)*x)*(a + c*x^2)^(p + 1))/(2*c*(p + 1)*(2*p + 3)), x] - Dist[(a*e*g - c*d*f*(2*p + 3))/(c*
(2*p + 3)), Int[(a + c*x^2)^p, x], x] /; FreeQ[{a, c, d, e, f, g, p}, x] &&  !LeQ[p, -1]

Rule 215

Int[1/Sqrt[(a_) + (b_.)*(x_)^2], x_Symbol] :> Simp[ArcSinh[(Rt[b, 2]*x)/Sqrt[a]]/Rt[b, 2], x] /; FreeQ[{a, b},
 x] && GtQ[a, 0] && PosQ[b]

Rubi steps

\begin{align*} \int \frac{(5-x) (3+2 x)^3}{\sqrt{2+3 x^2}} \, dx &=-\frac{1}{12} (3+2 x)^3 \sqrt{2+3 x^2}+\frac{1}{12} \int \frac{(3+2 x)^2 (192+93 x)}{\sqrt{2+3 x^2}} \, dx\\ &=\frac{31}{36} (3+2 x)^2 \sqrt{2+3 x^2}-\frac{1}{12} (3+2 x)^3 \sqrt{2+3 x^2}+\frac{1}{108} \int \frac{(3+2 x) (4440+5130 x)}{\sqrt{2+3 x^2}} \, dx\\ &=\frac{31}{36} (3+2 x)^2 \sqrt{2+3 x^2}-\frac{1}{12} (3+2 x)^3 \sqrt{2+3 x^2}+\frac{5}{54} (809+171 x) \sqrt{2+3 x^2}+\frac{275}{3} \int \frac{1}{\sqrt{2+3 x^2}} \, dx\\ &=\frac{31}{36} (3+2 x)^2 \sqrt{2+3 x^2}-\frac{1}{12} (3+2 x)^3 \sqrt{2+3 x^2}+\frac{5}{54} (809+171 x) \sqrt{2+3 x^2}+\frac{275 \sinh ^{-1}\left (\sqrt{\frac{3}{2}} x\right )}{3 \sqrt{3}}\\ \end{align*}

Mathematica [A]  time = 0.0463444, size = 50, normalized size = 0.6 \[ \frac{1}{27} \left (825 \sqrt{3} \sinh ^{-1}\left (\sqrt{\frac{3}{2}} x\right )-\sqrt{3 x^2+2} \left (18 x^3-12 x^2-585 x-2171\right )\right ) \]

Antiderivative was successfully verified.

[In]

Integrate[((5 - x)*(3 + 2*x)^3)/Sqrt[2 + 3*x^2],x]

[Out]

(-(Sqrt[2 + 3*x^2]*(-2171 - 585*x - 12*x^2 + 18*x^3)) + 825*Sqrt[3]*ArcSinh[Sqrt[3/2]*x])/27

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Maple [A]  time = 0.006, size = 65, normalized size = 0.8 \begin{align*} -{\frac{2\,{x}^{3}}{3}\sqrt{3\,{x}^{2}+2}}+{\frac{65\,x}{3}\sqrt{3\,{x}^{2}+2}}+{\frac{275\,\sqrt{3}}{9}{\it Arcsinh} \left ({\frac{x\sqrt{6}}{2}} \right ) }+{\frac{4\,{x}^{2}}{9}\sqrt{3\,{x}^{2}+2}}+{\frac{2171}{27}\sqrt{3\,{x}^{2}+2}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((5-x)*(3+2*x)^3/(3*x^2+2)^(1/2),x)

[Out]

-2/3*x^3*(3*x^2+2)^(1/2)+65/3*x*(3*x^2+2)^(1/2)+275/9*arcsinh(1/2*x*6^(1/2))*3^(1/2)+4/9*x^2*(3*x^2+2)^(1/2)+2
171/27*(3*x^2+2)^(1/2)

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Maxima [A]  time = 1.50345, size = 86, normalized size = 1.02 \begin{align*} -\frac{2}{3} \, \sqrt{3 \, x^{2} + 2} x^{3} + \frac{4}{9} \, \sqrt{3 \, x^{2} + 2} x^{2} + \frac{65}{3} \, \sqrt{3 \, x^{2} + 2} x + \frac{275}{9} \, \sqrt{3} \operatorname{arsinh}\left (\frac{1}{2} \, \sqrt{6} x\right ) + \frac{2171}{27} \, \sqrt{3 \, x^{2} + 2} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((5-x)*(3+2*x)^3/(3*x^2+2)^(1/2),x, algorithm="maxima")

[Out]

-2/3*sqrt(3*x^2 + 2)*x^3 + 4/9*sqrt(3*x^2 + 2)*x^2 + 65/3*sqrt(3*x^2 + 2)*x + 275/9*sqrt(3)*arcsinh(1/2*sqrt(6
)*x) + 2171/27*sqrt(3*x^2 + 2)

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Fricas [A]  time = 1.7754, size = 158, normalized size = 1.88 \begin{align*} -\frac{1}{27} \,{\left (18 \, x^{3} - 12 \, x^{2} - 585 \, x - 2171\right )} \sqrt{3 \, x^{2} + 2} + \frac{275}{18} \, \sqrt{3} \log \left (-\sqrt{3} \sqrt{3 \, x^{2} + 2} x - 3 \, x^{2} - 1\right ) \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((5-x)*(3+2*x)^3/(3*x^2+2)^(1/2),x, algorithm="fricas")

[Out]

-1/27*(18*x^3 - 12*x^2 - 585*x - 2171)*sqrt(3*x^2 + 2) + 275/18*sqrt(3)*log(-sqrt(3)*sqrt(3*x^2 + 2)*x - 3*x^2
 - 1)

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Sympy [A]  time = 1.17184, size = 80, normalized size = 0.95 \begin{align*} - \frac{2 x^{3} \sqrt{3 x^{2} + 2}}{3} + \frac{4 x^{2} \sqrt{3 x^{2} + 2}}{9} + \frac{65 x \sqrt{3 x^{2} + 2}}{3} + \frac{2171 \sqrt{3 x^{2} + 2}}{27} + \frac{275 \sqrt{3} \operatorname{asinh}{\left (\frac{\sqrt{6} x}{2} \right )}}{9} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((5-x)*(3+2*x)**3/(3*x**2+2)**(1/2),x)

[Out]

-2*x**3*sqrt(3*x**2 + 2)/3 + 4*x**2*sqrt(3*x**2 + 2)/9 + 65*x*sqrt(3*x**2 + 2)/3 + 2171*sqrt(3*x**2 + 2)/27 +
275*sqrt(3)*asinh(sqrt(6)*x/2)/9

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Giac [A]  time = 1.13243, size = 66, normalized size = 0.79 \begin{align*} -\frac{1}{27} \,{\left (3 \,{\left (2 \,{\left (3 \, x - 2\right )} x - 195\right )} x - 2171\right )} \sqrt{3 \, x^{2} + 2} - \frac{275}{9} \, \sqrt{3} \log \left (-\sqrt{3} x + \sqrt{3 \, x^{2} + 2}\right ) \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((5-x)*(3+2*x)^3/(3*x^2+2)^(1/2),x, algorithm="giac")

[Out]

-1/27*(3*(2*(3*x - 2)*x - 195)*x - 2171)*sqrt(3*x^2 + 2) - 275/9*sqrt(3)*log(-sqrt(3)*x + sqrt(3*x^2 + 2))